## Misunderstanding of functions in R

I have a vector

```
p <- seq(0,1,length=11)
```

That I want to use as the independent variable in the summation

If I craft a function that codes the summation by hand

```
f <- function(a){
a^0*(1-a)^5+a^1*(1-a)^4+...
}
```

and pass it `p`

, then I get the correct output and no errors are thrown

```
results <- f(p)
```

I can plot it, `results`

is the right length, everything's kosher. It just looks really ugly so I wanted to use `sum()`

instead and tried

```
i <- 0:5
g <- function(a,i){
sum(a^i*(1-a)^(5-i))
}
```

but when I attempt `g(p,i)`

it throws the error

```
longer object length is not a multiple of shorter object length
```

I believe the reason I'm getting this error is answered over here quite nicely, especially the part about recycling. `sum`

cycles through the `i`

vector as well as `p`

at the same time, then starts over with `p[7]`

and `i[1]`

when it runs into the end of `i`

. My question, however, is what is the CORRECT way to simplify `f`

into `g`

?

Show source

## Answers to Misunderstanding of functions in R ( 3 )

Maybe try this:

The function that you want to compute isn't naturally vectorized with respect to

`p`

.`sapply`

is a natural choice for mapping non-vectorized functions over a vector:I'd do something like this,

To answer your question, I don't think there is

one correct wayto do this; a more functional approach might bebut it's likely to be less efficient, and arguably less readable.