## ApplicativeDo not working with sequencing

Question

I have this type, basically a Kleisli arrow:

```
{-# language DeriveFunctor #-}
data Plan m i o = Plan (i -> m o) deriving Functor
instance (Monad m) => Applicative (Plan m i) where
pure x = Plan (\_ -> pure x)
Plan f <*> Plan x = Plan (\i -> f i <*> x i)
```

Since it has an `Applicative`

instance, I turn on `ApplicativeDo`

and try to build a value using do-notation:

```
{-# language ApplicativeDo #-}
myplan :: Plan IO () ()
myplan = do
pure ()
pure ()
```

It doesn't work:

```
No instance for (Monad (Plan IO ())) arising from a do statement
```

Is there a way to make it work? I'm using GHC 8.0.1.

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## Answers to ApplicativeDo not working with sequencing ( 2 )

`ApplicativeDo`

does not mean that`do`

expressions willalwaysbe desugared in terms of an applicative functor, but only if it makes sense to do so. Here, it does not. If you have a`do`

expression likenote that the order doesn't really matter, so you could desugar this to

instead of

However, the expression

doesn't have any way of being expressed using

`pure`

and`<*>`

alone. It isnotequivalent to`pure () <*> pure ()`

, because the first value wraps`()`

, not a function. Since there is no valid way to desugar this using only an`Applicative`

instance, the compiler looks for, and fails to find, a`Monad`

instance to allow`pure () >> pure ()`

.After searching for

`ApplicativeDo`

-related tickets in the GHC Trac, it appears that is is a known problem:https://ghc.haskell.org/trac/ghc/ticket/10892

https://ghc.haskell.org/trac/ghc/ticket/12666

Explicitly discarding the result is a workaround: